How long can a 12V 75A battery with a 3000W pure sine wave power inverter drive a 40W refrigerator?

To calculate how long a 12 volt 75 amp-hour battery with a 3000w pure sine wave power inverter can drive a 40 watt refrigerator, we must first calculate the operating current of the refrigerator. According to I=P/U (power grid voltage), the available refrigerator current=40W/220V≈0.2A. Power supply time=battery capacity/refrigerator current=75Ah/0.2A=375h. Multiplying 375h by the conversion efficiency of your pure sine wave inverter is the final result. If your pure sine wave inverter conversion efficiency is very low, then the power supply time will be greatly shortened. Therefore, when buying a pure sine wave inverter, you must see whether its conversion efficiency is high enough. Our suggestion is that a pure sine wave inverter with a conversion efficiency of less than 80% has no purchase value.

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